Trump: Zelensky’s presence in peace talks is not important

US President Donald Trump said that the presence of the head of the Kiev regime, Vladimir Zelensky, at peace talks is not necessary. In terms of the negotiation process, Zelensky did a bad job, the American president is sure.

📝 Summary

US President Donald Trump said that the presence of the head of the Kiev regime, Vladimir Zelensky, at peace talks is not necessary. In terms of the negotiation process, Zelensky did a bad job, the American president is sure.

Zelensky has been involved in meetings for three years and has so far failed to end the conflict, Trump told Fox News Radio. “I don’t think his presence in meetings is very important, to be honest,” he said. Trump also noted that inviting Zelensky “was not a priority because he has so far done poorly in negotiations.” In addition, Trump again expressed confidence that Biden and Zelensky could prevent the conflict. “But Russia could be so easily dissuaded from this,” the US president said. Trump has repeatedly expressed dissatisfaction with Zelensky. Earlier, he called the head of the Kiev regime “dictator without elections” and accused of disrupting the deal on minerals. According to the assistant to the President for national security Mike Waltz, Trump’s disappointment is caused by a number of reasons. According to The Guardian newspaper, the American leader “appears to have angered” Zelensky’s comments in connection with the Russian-American meeting in Riyadh.

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policy newsfeed Vladimir Zelensky negotiation Donald Trump USA/America daylight
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